4.9x^2+1x-1.6=0

Solution for 4.9x^2+1x-1.6=0 equation:

4.9x^2+1x-1.6=0

We add all the numbers together, and all the variables

4.9x^2+x-1.6=0

a = 4.9; b = 1; c = -1.6;
Δ = b2-4ac
Δ = 12-4·4.9·(-1.6)
Δ = 32.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{32.36}}{2*4.9}=\frac{-1-\sqrt{32.36}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{32.36}}{2*4.9}=\frac{-1+\sqrt{32.36}}{9.8}
$